e Exam Runs; I Mean If You Want To Receive The Earlyface Real Answers Direct to Your Phone Number as Text Messages (SMS) Before You enter Examination Hall. Please Select/Click On The particular Exams Below to Read the Procedures to Get any Of them; Click Here To Read; How To Get All 2013 NECO Correct Solved Answers Direct To Your Phone As Text Messages (SMS) . CURRENT EXAMINATION: NECO Mathematics;[/ size) Verified MATHS OBJ: 1-10: BCABCADDAA 11-20: DDEACDBACA 21-30: ABAACECADB 31-40: ACAEBEBBCD 41-50: EDEDDEDDCA 51-60: CADCEDDEAB THEORY; (quote) / means DIVISION * means multiplication tita u should know dat. rais means raise to power ^ means raise to power sqr rut/ squar rut means square root ----(1) means equation 1 yr means year f(x-xbar) means x MINUS x BAR as in statistics which means that MINUS WILL BE ON TOP OF x. , (Comma) means NEXT LINE, (/quote) (1) n(AUBUC)=n(A)+n(B)+n (C)-n(AnB)-n(BnC)+n (AnBnC) 55=21+24+23-6-8-5+2 x+x 55=49+3x 3x=6 x=2 (1i) 21-6-5-x = 21-11-2 physics only=8 (1ii) 6+5+8= 19 (2a) Using almighty formular x= -b+sqrt(b^2- 4ac) /2a =5+sqrt(25-4(2)(3))/ 2(2) =(5+1)/4 or (5-1)/4 = 1 or (1)1/2 (2b) Volume of cylinder= pieR^2h 352=22/7*4*4*h h=7 (3a) RD^2=(37)^2- (12)^2 = 1369-144 RD^2=1225 RD=sqrt(1225) =35cm Area= 35*12=420cm^2 (3b) ((2p+q)/(p-3q))^1/2=h sqrt(h)=(2p+q)/(p-3q) Psqrt(h)- 3qsqrt(h)=2p +q Psqrt(h)-2P= q+3qsqrt (h) P(sqrt(h)-2)= q+3qsqrt (h) P=q+3qsrt(h)/sqrt(h) -2 (4a) (n-2)180= xn+x=180 x(n+1) 180n-360=xn+x 180n-360=x(n+1) x=180n-360/n+1 (4b) (x+5)/3-(2x-1)/5=5/6 30((x+5)/3) - 30((2x-1) /5)= 30(5/6) 10x + 50-12x+6=25 56-2x=25 -2x=-31 x=15.5 (5a) perimeter of sector= (tita/360)2pieR+2r =2(9) +120/360*2*22/7*9 =18+18.86 =36.9cm (5b) 150/h=tan30 h=150/tan30 h=259.8 approx 260 (6a) Snth= n/2(2a+11d) -192=24a+132d -96=12a+66d -32=4a+22d -16=2a+11d ----equ(1) -252=18(2a+17d)/2 -504=18(2a+17d) -28=2a+17d-------equ (2) (-16=2a+11d) -(-28=2a+17d) 12=-6d d=-2 (6b) from equ(1) -16=29+11(-2) -16=29-22 2a=6 a=3 (6c) Tnth= a+(n-1)d =3+(15-1)(-2) T15th= -25 T4th=a+(4-1)d =3+3(-2) =-3 Product of 15th and 4th= -3*-25=75 (7ai) STB= 180-75-40 (sum of angles on a straight line) STB= 65 SRP= 180-65(opposite angles are complementary) =115degree (7aii) SQP= 115(angles substended from the same circumference are equal) (7aiii) SPQ=180-115-12 (sum of angle in a triangle) =53degree (7b) C=R+KT 2800=R+K(6) 2800= R+6k ---------equ (1) - 3600= R+10K------equ (2) -800 = -4k k=200 From eqn(1) 2800=R+200(6) 2800=1200R R=2(1/3) at 4hours, C= 2(1/3) + 200(4) = 800 +2(1/3) =80
Posted on: Thu, 27 Jun 2013 11:17:39 +0000
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