(No 3) I= OA V=1.3V Tabulate: S/N: 1,2,3,4,5,6 I(A):0.50,0.90,1.40,2.00,2.50,3.00 V(v): 1.27,1.24,1.20,1.17,1.14,1.12 (3Vi)Slope=change in V/change in I =1.28-1.12/2.75-0.35 =0.16/2.4 =0.066 =0.07VA^-1 Intercept=1.29v (3Vii)Z=c/v.=1.3/1.3=1 (3X)Precautions: -I would ensure that the connecting wires -I would avoid error due to parallax when reading voltmeter and ammeter. (3bi) -length -cross sectional area -temperature -type of material (3bii) Specific resistance of a piece of wire refers to the amount of opposition the wire will offer to the flow of electric current through it. (3biii) Given data E1=7.5v E2=7.5v E3=7.5v Et=E1=E2=E3=7.5v r=3 ohms R=5 ohms I=??? Et=I(r+R) 7.5=I(3+5) 7.5=8I I=7.5/8 I=0.9375 I=0.94A Pls dont forget to advertise the site Examflavour
Posted on: Fri, 01 Nov 2013 09:14:59 +0000