SUMMARY OF PHYSICS PRACTICAL ANSWERS (1Vii) Draw a table S/N: 1,2,3,4,5 D/cm: 140,120,100, 80,62 T/s: 1.25,1.10,0.93,0.83,0.72 W/ms-1: 1.12,1.10,1.08,0.96,0.83 V (ms-1): 224,220,216,193,167 (1ix) Slope = (Y2-Y1)/ (X2-X1) ms/S = (216 -167 ) / (0.93 -0.72) ms/S = 49/0.21 = 233.3 (x) It determines the ratio of the distance moved by effort to the distance moved by load. (1XI) Precautions: - I ensured that the readings were taken without any error - I ensured the mass roll down freely as being influenced under gravity (1bi) Velocity Ratio(V.R) = i/ sin(tita) = 1/ (h/d) V.R = D/h h= height of inclinde plane (1bii) mass of object(m)= 5kg Angle of inclination(tita)= 30degree Force(F) Perpendicular to the plane is F= mg Sin(tita) F= 5*10*Sin30(degree) F= 25N (3a) (vi) I=0.35A PLS DRAW A TABLE. i: 1,2,3,4,5 Xi(cm): 20.0,35.0,45.0,60.0,80.0 x^-1: 0.0500,0.0285,0.0222,0.0167,0.0125 I(A) : 1.50,1.45,1.35,1.30,1.25. ======= NOTE: ^ means raise to power. i: means that under i, u will get 1,2,3,4,5.. ======== (3viii) Slope,S=y2-y1/x2- x1 =(0.4000-0)cm-1/(1.500-1.125)A =0.4000 cm^-1/0.375 A =1.0667 cm-^1 A-^1 (ix)the value of Ii for which X-1=0 is 1.125A (x) I./ I=1.125A/0.350A =3.214 (3xi) 1. I ensured that the key is not closed when no reading are not taken. 2. I ensured the circuit parameters are tightly connected to ensure accurate result. 3. I ensured that the jockey touches the exact point on the potentiometer wire. (3bi) EMF of a battery is the potential difference between the terminals of a cell when no current flows in the circult. (3bii) Given, Vx=1.018V Lx= 50.0cm Vy=? Ly=75.0cm Vx/Lx = Vy/Ly 1.018/50 = Vy/75 Vy= (1.018 * 75)/50 Vy= 1.527V === COMPLETED === Am nt 100% sure abt dis ans.. Pls take note it may hlp you.. HOSTED BY: Http://officialbaze.ga
Posted on: Wed, 10 Sep 2014 22:16:42 +0000
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