TO : University Of Strathclyde Department Of Mechanical Engineering Me Ooi Kean Teik Graduation In Years 1991 2nd Upper Honours Degree Mechanical Engineering Student Final Year Thesis Title : Spherical Pressure Vessel Design Finite Element Analysis (ANSYS) Purpose : When The Spherical Will Exploding And In What Value And Why Its Exploding Present Date : 18 - 6 - 2013 Malaysia Time : 12 : 06 Noon I Submitted My Continues Research By On The Same Title Same Research Requirement For My Ph.D In Mechanical Self Studying And Improvement Of Environment Research Spherical Pressure Vessel Design BS5500 Secondary Yield Strain = Maximum Shear Strain Secondary Yield Strain < Secondary Strain Ha Ha Ha I Just Know Its The Theory And Solution Since Studying And Research In 1991 I Only Need 6 Months To Calculate The Value And Result Then I Will Getting The Ph.D In December 1991 By 1st Degree Holder Student Actually I Only 2nd Upper And Can Not Continues The Course And I Just Know The Result And Outcome : Secondary Yield Strain = Maximum Shear Strain By The Universal Mathematics Equation Yield Strain = Strain x + Strain y = Secondary Strain + Primary Strain = -1 + +1 = 0 Secondary Yield Strain = Maximum Shear Strain = Shear xy/2 = ( Shear Secondary + Shear Primary ) / 2 Structural = 0 Yield Stress = Stress x + Stress y = Secondary Stress + Primary Stress Stress y = Primary Stress = 0 Yield Stress = Secondary Stress = 1 = 0 = -1 + +1 = -1 = +1 Hence Secondary Yield Strain = ( Shear Secondary + Shear Primary ) / 2 Primary Stress = Primary Strain = Primary Shear = 0 Secondary Yield Strain = Secondary Shear / 2 = -1 / 2 By, Ooi Kean Teik Date : 16 - 6 - 2013 Time : 2 : 08 Conclusion : 1. My Thesis 1991 Already Proof That The Exploding Is Caused By The Secondary Strain Expanding Works Which Is Based On One USA Scientist Research Paper Report And I Analyse The Practical Result Total Match With His Theory 2. The Explosion Of Spherical Pressure Vessel Design Is Based On The Secondary Strain Expanding Works And Its Will Exploding On And By The Secondary Yield Strain = Secondary Shear / 2 = -1 / 2 Based On BS5500 1990
Posted on: Tue, 18 Jun 2013 05:34:00 +0000
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