+++++++++++++++++++++++++++ Verified PHYSICS OBJ: 1-10: DBAABCDCBC 11-20: CDCCDBADDA 21-30: AACAACCCAC 31-40: CCACBADBCC 41-50: ABBCBBCDDC +++++++++++++++++++++++++++ TAKE NOTE OF THIS ABEG!!! ON NO CONDITION SHOULD YOU WRITE POWER ON YOUR PAPER. I USED POWER TO EXPRESS RAISE TO POWER. ANYWHR U SEE POWER, RAISE THE NUMBER UP INSTEAD OF WRITING POWER PLS OOOO. ===================== sqrt means square root sign ie _/ V=sqrt(80) means V= _/80. DONT WRITE sqrt +++++++++++++++++++++++++++ (1a) F= Force, m= Mass, a= Acceleration F is directly proportional to (m) F/a=ma/a m=F/a (N/m) (1b) Dimensionally analysis for m=M since F= MLT power-2 a=LT power-2 hence, F/a=MLT power-2/LT power-2 :. Dimension for m = Dimension for F/a which is M This implies that the equation is dimensionally correct =============================== (2) U=20m/s S=125m t=? g=10m/s power-2 S=ut + i/2at power2 125= 20t + 1/2(10)t power 2 125=20t + 5t power 2 5t power 2 + 20t-125=0 Dividing through by 5 5t power 2/5 + 20t/5 -125/5 =0/5 t power 2 + 4t - 25=0 solving the equation quadratically, using general method t= -bt + sqrt(b power 2)-4ac/2a t= -bt - sqrt(b power 2)-4ac/2a a=1, b=4, c= -25 t= -4 + sqrt(4 power 2-4(1)(-125)/ 2*1 t= 4 + sqrt(16+500)/2 t= 4+ sqrt(416)/2 t= 4 + 20.4/2 or 4-20.4/2 t= 24.4/2 or -16.4/2 hence, t=12.25 or -8.25 so the time it takes the ball to reach the ground (t)=12.25 ================================ (3a) i. The angle which the object makes with the horizontal line ii. acceleration due to gravity (3b) At maximum range tita= 45degree ========================= (6) m= 9.1*10 power -31kg v=6.6*10 7m/s wavelenght= ? h=6.6*10 power -34Js wavelenght =h/meV V= sqrt(2eV/me) wavelenght= 6.6*10 power -34/ (9.1*10 power -34)*(6.6*10 power -7) =1/9*10 7 wavelenght= 0.11*10 power 7 wavelenght=(1.1*10 6)1electrovolt 1electrovolt = 1.6*10 power -19 wavelenght=(1.1*10 power -6) (1.6*10 power -19) =1.76*10 power -13m ======================
Posted on: Tue, 16 Sep 2014 10:51:55 +0000
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