Chemistry Answers (1a) NOTE THAT ^ MEANS Raise to power. PLS DRAW UR TABLE AS USUAL AND INPUT THE FOLLOWING: Burette reading: final burette reading(cm^3) Initial burette reading (cm^3) Volume of acid used(cm^3) |Rough|:22.40,0.0 ,22.40, |1st|:22.00,0.00,22.00 |2nd|:22.00,0.00,22.00 |3rd|:22.00,0.00,22.00 Average titre value=22.00+22.00+22. 00/3 =22.00cm^3 (1biii) molar of HCl=1+35.5=36.5g Concentration of A in gdm^-3 =molar mass * concentration in moldm^ -3 =36.5*0.209=7.63gdm^ -3 (1bi) 2.45=250cm root 3 Xg= 1000cm root 3 Xg = 1000x2.45/250 =2450/250 Xg = 9.8gdm^-3 Cb=conc. Of B in moldm^-3 Molar mass of Na2CO3=23*2+12+3*16 = 106g Cb= concentration in gdm^-3/molar mass =9.8/106=0.09245 moldm^ -3 Concentration of B in moldm^3 = 0.0925 moldm -3. (1bii)CAVA/CBVB = na/nb Where ca= concentration of acid in moldm^-3 Cb =concentration of base in moldm^-3 VA= volume of acid Vb= volume of base Na=no of mole of acid Nb=no of mole of base Ca= CB*VB*na/va * nb Ca = 0.0925*25*22.10*1 Ca= 4.625/22.10 = 0.209 moldm
Posted on: Thu, 10 Apr 2014 09:29:37 +0000
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