Mayesa Dasa’s THE UNIVERSAL FORMULA Chapter One I offer my obeisance’s to His Divine Grace A.C. Bhaktivedanta Swami Prabhupada, my spiritual master. Some years ago I was planning a trip to India. I was informed by a devotee Godbrother, Bhima dasa that preparation for the Temple of understanding was underway. He asked if I should like to participate while in India. I jumped at the chance knowing my spiritual masters desire to create a Vedic planetarium. Like most of my Godbrothers I knew nothing of any magnitude regarding Vedic cosmology. After spending time with His Divine Grace Danavir Gosvami and his team of researchers I became evermore desirous of breaking what I had come to believe was a mathematical code in the 5th canto of Srimad Bhagavatam Purana. Morning Walk December 17, 1973 Los Angeles, California Srila Prabhupada: In Bhagavatam there is regular calculation what is the distance from one planet to another. I hereby present my findings. Background Before tackling the formula for the planetary distances a little background will be helpful to the reader. We find the formula for calculating the distances to the planets in the 5th canto of Srimad Bhagavatam. The 5th canto begins with a description of Maharaja Priyavatta creating Bhuhalasva. Bhuhulasva is a division of seven islands and seven oceans. The central island is named Jambudvipa. Jambudvipa is surrounded by the first circular ocean. In this way there are six more concentric circles of land and six oceans between each circular island. We cannot assume that these divisions only exist for a short time but rather that they exist in every day of Brahma. This means that 5th canto recounts Maharaja Priyavatta recreating these seven islands and seven oceans after what is called the partial deluge. It is described there Maharaja Priyavatta creating a special chariot for digging out the boundaries which shall make up Bhuhulasva. This suggests that Bhuhulasva is either only created once or that Bhuhulasva had been destroyed temporarily and had to be recreated or re-subdivided. Here are some verses from various Puranas describing the situation of Bhuhulasva during the partial deluge and describing Bhuhulasva being lifted into place by Lord Varaha at that time. Srimad Bhagavatam canto 1 Chapter 13 text 15 Commentator AC Bhaktivedanta ...but Sri Jiva Gosvami has given definite proofs from authoritative scriptures (like Visnu-dharmottara, markandeya purana, harivamsa,etc ) that there is always a devastation after the end of each and very Manu.... Skanda Purana part IV page 207 Publisher Motilal Banarsidass Towards the close of a day of Brahma o son of Pandu, a terrible drought lasting for a hundred years befalls the earth.... At that time the sun will be endowed with ray that will resemble fire...With the villages, cities, mountains, trees, forests, etc perished, the earth then becomes comparable with the back of a tortoise. It will resemble a red-hot ball of fiery iron. Then from the limbs of the creator great clouds will issue forth...With that great water the great fire caused by the sun will be extinguished. That water poured down by the clouds at the close of the kalpa spreads to all the worlds. A dense darkness envelops the worlds of Bhuh, Bhuvah, Svah and Mahah. The earth sunk under water goes down to the bottom of the nether worlds.It does not perish... When the night passes off, he gets up quickly and as before creates all the creatures at the behest of Hari. Srimad Bhagavatam canto 3 chapter 13 text 18 – O sinless Vidura, all of a sudden, while Brahma was engaged in thinking, a small form of a boar came out of his nostril... Padma Purana Part 1 page 20 Motilal Banarsidass publisher - Having lifted up the earth (from the ocean) with its fang rose like a great blue mountain...the highest soul, who had held the earth, being thus praised, put it in the great ocean. The earth remained over it like a boat in a stream of water. The beginingless Supreme Being, then having flattened the earth, piled the mountains on it according to (its) divisions. Then having accurately divided the earth into seven divisions, he conceived the four worlds bhuh etc. as before. Mahabharata SectionSanti Parva Section CCCXLVI page 177 Translation by Gangula - Nara and Narayana said, The earth, in days of yore, with her belt of seas, disappeared from the view, Govinda, assuming the form of a gigantic boar, raised her up (with his mighty tusk) Varaha Purana Part 1 Chapter 89 Motilal banarsidass publisher - Then in this broad earth forming part of the expansive universe, these are the regions enumerated. In every aeon Lord Narayana assumes the form of a boar and raises it up by a tusk and restores it to its original position. There are many more such verses. (We learn that not only our earthly planet but the whole of bhuhulasva is burnt and is covered by water during the partial devastation. We learn that after that period bhuhulasva is lifted back into place by the lord Varaha and divisions of bhuhulasva are restored. In some case a person such as maharaja Priyavatta will restore them and in other cases lord Varaha digs them out. I have left off those verses.) Bhuhulasva The circumference of these seven oceans and seven islands is 640,884,901.3 miles. (We calculate a yojana as eight miles) Sun In the 6th chapter of 5th canto of Srimad Bhagavatam we are given the length of the suns chariot. My dear king, the carriage of the sun-gods chariot is estimated to be 3,600,000 yojanas [28,800,000 miles] long... Not only the sun but also other planets are described as chariots. Matsya Purana Chapter CXXVII - Suta said:-I shall now relate to you about the chariots of the stars and planets...the chariot of Budha (Mercury, the son of the Moon) is brilliant and white.—1 It is drawn by ten horses... Matsyamahapuranam Nag Publishers If we take what is termed chariot as the greatest distance the sun travels in a muhurta (48 minutes) then we can multiply the number of muhurtas in a day (30) by 28,800,000 which gives us 864000000. Coincidentally there are 86400 seconds in a day. In 5th canto Srimad Bhagavatam 12th chapter we find other measurements for the sun. 8,640,000,000 is the circumference of the sun at 23.5 degrees approximately. The Formula There is a verse in the 5th canto chapter 12 text 14 - As in an oil-pressing machine, the first axle is attached to a second axle, which is one-fourth as long [3,937,500 yojanas, or 31,500,000 miles]. The upper end of this second axle is attached to Dhruvaloka by a rope of wind. We may take not that the second axle is not described as horizontal or perpendicular. It is attached to Dhruva by a circular wind Background The number 31,500,000 is the suns axle. The number 640,884,901.3 is the circumference of bhuhulasva. The number 31,500,000 contains within it the distance from the earth (1,600,000) This is not the actual distance of anything-this number is meant to be used as part of a formula. 1,600,000 must be added to the figure 640,884,901.3 This will become clear as we proceed. Here is the formula to derive the distance and movement of the sun. Step one - 31,500,000 / ((640,884,901.3 + 1,600,000 ) / 360 )) = 17.65022023 Step Two - 17.65022023 X 1577917828 = 2785059716... Divide by 100 = 278505971.6 / 2 = 139252985.8 In the case of the sun we know that its circumference is 864,000,000. Subtract 139252985.8 from 864,000,000 = 724,747,014.2 Now we can draw two different kinds of diagrams to show what we have found. We see plainly that the sun appears to move away from earth as it journeys to the south. Modern science does not know of this movement. This would also require the sun to grow in size so that it does not appear smaller when it moves away from earth. And it would require that the clouds around the sun are water drawn there in molecular form, which will be expelled later. This means the sun draws water for six months. Observation When we observe the sun through telescope all we can see are clouds around the sun. Scientists speculate these are gasses. Math I am fully aware that the reader may not have background in math but explanation of all math will be given in due course. By the end of this book the reader will be able to do the calculations. End Chapter One Illustration 2 shows how we can calculate the movement. The numbers here 125941894 and 150140385.9 are distances from earth to sun if earth planet were at the center of the movement of the planets. The hypotonuses ( slanting lines ) are distances north and south. This is a side view so we are showing radiuses. Mayesa Dasa’s The Universal Formula Chapter two Rahu At the risk of getting ahead of ourselves we shall examine a calculation for Rahu. This will appear later but we shall examine it now because of the unique understanding it will give us in reference to the moon. Srimad Bhagavatam 5th canto chapter 9 text 1 Srila Sukadeva Gosvami said:My dear king, some historians, the speakers of the puranas, say that 10,000 yojanas [80,000 miles] below the sun is the planet known as Rahu, which moves like one of the stars. First Step 31500000 - 80000 = 31420000 Second step 640884901.3 - 80000 = 640804901.3 Third Step 640804901.3 / 360 = 1780013.615 Fourth Step 31420000 / 1780013.615 = 17.65155038 Fifth step 17.65155038 X 1577917828 = 2785269604 / 2 = 1392634802 We will find the distance of the moon around our equator to be 706489952.8 706489952.8 - 13926348.02 = 692563604.8 That number is 11.39512927 degrees. One of the various forms of lunar eclipse. It happens when the moon is full. Astronomers observe that if the moon is within 11.38 degrees of a node (where the moon passes across our equator) there can be lunar eclipse of the full moon. This will show us how the formula gives us numbers that are internally consistent. Moon Srimad Bhagavatam 5th canto chapter 7 text 8 Above the rays of the sunshine by a distance of 100,000 yojanas [800,000 miles] is the moon... The moon is not as regular as the sun. The moon always moves at least 18.28 degrees north and south. But it also moves beyond that. Formula for the moon Step one 31500000 + 800000 = 32300000 Step two( 640884901.3 + 2400000) / 360 = 1786902.504 Step three 32300000 / 1786902.504 = 18.07597221 Step Four 18.07597221 X 1577917828 =285223988 / 8 = 3565299851 When we subtract 35652998.51 from 706489952.8 we get 670836954.3 670836954.4 is the moon at 18.28 degrees exactly Now we can diagram this Illustration 3 shows the diagram of the moon from the side at 18.28 degrees which we derive from the code of Srimad Bhagavatam 5th canto chapter 9 text1. The moon can move up to 28.8 degrees but always moves at least 18.28 degrees. Therefore the formula uses this number. A word about mathematics When we divide a number that is a circumference by a larger number of circumference we get a decimal. This decimal is called cosine. For example 22819.26469 is the circumference of the earth where the sun reaches its northernmost height When we divide that number by the circumference of the earth around its equator 24902 we get .91636273 If you consult a chart or have a small handheld calculator that provides the proper function you will find this number is cos 23.6 degrees When we say a planet is at zero degrees celestial that means it is even with our equator. Declination is the same as latitude. This denotes the degree to which a planet is above or below the earths equator. Sometimes plus is used to mean above the equator and minus to mean below the equator. But more properly this is north and south, respectively. What the declinations of the planets are can be found on Nasas website, or in an ephemeris, or various other places. i consulted Dr Lomb, a Phd. Diagram 4 shows us the diagram of the moon and the diagram of Rahu at 11.39 degrees, overlaid. The line AB is the moons angle of 18.28 AC is degree 11.39 AD is moons angle of zero degrees AE is moons angle of 11.39 AF is moons angle of 18.28 When the moon is not more than 11.39 lunar eclipse of the full moon can take place. As we continue we shall explain how the moon moves further away than the sun sometimes. And we shall demonstrate the logic of phases. And we shall speak at length about Rahu and give quotations to bulwark our discovery of the formula. End of Chapter Two The universal Formula Mayesa Dasa The Universal Formula Chapter Three Numbers Narada Purana Chapter 54 Published by Motilal Banarsidass 70. The number of terrestrial days in a (maha-yuga ) is 1,57,79,17,828. The number 1577917828 is the number of days in an age. By dividing this number by the number of revolutions for a planet we get the days of a single revolution. 1577917828 / 57753336 = 27.32 1577917828 / 4320000 = 365.25 Etc Surya Siddhanta Chapter 1 text 34 Published byHis Divine Grace Danavir Gosvami The number of revolutions ( bhagana ) for the stars is 1582237828. .. The constellations move at a different speed from the other planets. The number of days for the constellations revolution is determined like this 1577917828 + 4320000 = 1582237828 1582237828 / 4320000 = 366.25 The Formula The formula that we find in the Srimad Bhagavatam is precise. It is developed from a special mathematical principle. We have seen how by cosine we get a different degree of circumference. We could also subtract the lesser circumference from the greater and then divide that number by the greater circumference. This will give us a decimal. We can use that decimal to derive the distances to all the planets. That is so because the formula is designed to work in that way. We shall find for the Constellations and then demonstrate how this mathematical principle works. Constellations Srimad Bhagavatam Canto 5 Chapter 7 text 11 There are many stars located 200,000 yojanas [1,600,000 miles ] above the moon. By the Supreme will of the Supreme Personality of Godhead, they are fixed to the wheel of time, and thus they rotate with Mount Sumeru on their right, their motion being different from that of the sun. There are twenty-eight important stars, headed by Abhihjit Formula (31500000 + 2400000 ) / ( (Bhu + 5000000 ) / 360))= 1794124.7.. 33900000 / 1794124.7... = 18.89500742 18.89500742 X (1577917828 =+ 4320000) = 298963955 / 4 = The constellations are circumference 2168572242 2168572242 -74740988.75 = 2138675847 When we divide the lower number by the higher we have the cosine which is .986213789 This is cosine 9.524897182 Illustration 5 is of the constellations distance from the side Working out the formula In order to work the formula we must have some idea what should be the declination of the planetary body under consideration. In the case of the constellations a devotee friend Hridaynath dasa informed me that his father, a Vedic astrologer used 15 degrees for the constellations.But this did not work out and i was advised differently by a Phd at a Planetarium. But i shall revisit and rework these numbers later. The formula is giving us the numbers in between-the numbers to be subtracted from the largest circumference to derive the smallest circumference. Here is a way to prepare. We will use the planet earth as our circumference and an arbitrary number 24902 X cosine 15.01275719 = 24052.04929 24902 - 24052.04929 = 849.95071 849.95071 / 24902 = .034131825 Now if i have another object which I only know the subtracted number such as 16 X cosine 15.01275719 = 15.4538908 16- 15.4538908 = .5461092 Now if all i have is the number .5461092 I can get the number 16 by dividing .5461092 by .034131825 = 16 This is why we must have some idea what is the declination of a planet we are seeking with the formula If you work with this it will become clear. Siddhaloka,etc Srimad Bhagavatam 5th canto chapter 9 text 4 Below Rahu by 10,000 yojanas [80,000 miles] are the planets known as Siddhaloka, Caranaloka and Vidyadhara-loka. Formula 31500000 - ( 80000 + 80000) = 31340000 640884901.3 - (80000 X 2) = 640724901.3 640724901.3 / 360 = 1779791. 393 31340000 / 1779791.393 = 17.60880524 17.60880524 X (1577917828 + 4320000 ) = 2786131776 / 2 = 1393065888 These three planets, Siddhaloka, Caranaloka and Vidjadhara-loka are said to be below Rahu. In the verse previous to this ( we have already done the math in the second chapter of this book) Rahu was found at 11.39 degrees Therefore Siddhaloka, etc cannot be in the area of Dhruvaloka. These three planets are in fact called by us, Orions belt in the constellation Aries. Therefore they are part of the constellations. These three planets have three different declinations. The highest of the three is at approximately 2 degrees north. 2168572242 - 1393065.888 = 2167179176 Now let us see if this is 2 degrees 2167179176 / 2168572242 = .999357611 That is cosine 2.053808418 This confirms that our formula is correct. We have now proved for Moon and Rahu and showed how these two independently confirm each other. We have found for constellations and Siddhaloka,etc and showed how these planetary bodies confirm each other. The formula continues to verify itself. These are not isolated cases. The reader may have noticed that we sometimes disregard the placement of a decimal This is because the formula is designed this way. After all, this simple formula has been designed so that it is adaptable for large and small numbers. The reader may also have noticed we sometimes multiply by 2 or 4 or divide by 2 or 4. The same reason supports both cases-the formula is deliberately designed in this way. End of Chapter Three The Universal Formula The illustrations shows how the highest planet in Orions belt is merely 2 degrees north of celestial zero degrees. The third star is just under zero degrees celestial at .21 degrees Mayesa Dasa Chapter Four A word about the formula The second axle of the sun is given to us as 31500000. If the earth is 1600000 miles above the earth that number 1600000 (or whatever it is) should already be included for the sun. The second aspect of the formula is the second earth which is 640884901.3. That does not include 1600000 miles. So when we come to the moon we have added to 31500000+800000 With 640884901.3 we have added the 1600000 for the sun and 800000 for the moon This is apparently working nicely. However if we find that we have miscalculated we can go back and correct it. But as this formula will give us all of the planetary bodies in the bhagavatam I will carry it out as i am using it. History The reader may take notice that we are essentially working with circles. They are not complete circles of course. (when viewed from the side as in our diagrams) The ancient Greeks spoke of crystal spheres. Modern scientists not knowing this science have ridiculed the idea of concentric spheres. As we study ancient books we shall find many ideas were there that gradually were lost one by one until there was nothing remaining of this system. We frankly do not know how long this system has been lost to humanity. But in ancient books we will find mention of a second earth ( bhuvulasva) and as late as Rene Descartes we find the acceptance of the constellations as a region of angelic beings. IThus modern scientists characterize these mentions of chariots(grreek,angelic beings Descartes, second earth as figments of the fertile imagination and foolish superstitions of primitive men (as modern science thinks everything before now was primitive and they themselves are the apex of civilization) 7 Sages (Big Dipper) Formula 31500000 + 800000 + (5 X 1600000 ) + 8800000 = 50700000 640884901.3 + 5000000 + ( 5 X 1600000 ) + 8800000 = 662684901.3 662684901.3 / 360 = 1840791.393 50700000 / 1840791.393 = 27.54250166 27.54250166 X (1577917828 + 4320000) = j / 4 = 1089469700 The Constellations, the 7 Sages and Dhruvaloka move together Therefore they are to be calculated together. Therefore we subtract 1089469700 from the constellations 2168572242 to get the 7 sages. We must bear in mind we are finding the distances of the planets by way of a formula, which is specially designed for that purpose. Now we shall calculate for Dhruvaloka and then we will show how these three work together. Dhruvaloka Formula 31500000 + 2400000 +(5X1600000) + 8800000 + 10400000 = 61100000 640884901.3 + 5000000 + (5 X 1600000 ) + 8800000 + 10400000 + 673084901.3 673084901.3 / 360 = 1869680.281 = 32.67938407 32.67938407 X (1577917828 + 4320000 ) = j X 2 = 1034131153 So we have the constellations at 2168572242 The constellations are 9.51092039 degrees north and south So 2168572242 X cosine 9.510592039 = 2138765374 Our formula derived the number 1089469700 for the 7 Sages So 2138765374 - 1089469700 = 1049295674 When we divide 1049295674 ( 7 Sages ) by 2168572242 ( Constellations ) we get .483864754 That is cosine 61.06187908 Which is where the topmost star of the 7 Sages is located. Next we subtract the figure we derived from our formula for Dhruvaloka from 1049295674 Thus 1049295674 - 1034131153 = 15164521 15164521 / 2168572242 = .006992859 which is cosine 89.59933543 This matches what modern science determines for the North Pole Star ( Dhruvaloka) Modern science find is at 89.45 so we are very close IMPORTANT NOTE In fact I feel that our numbers are off ( our own fault) just a little so for now I am making Dhruva to be 18924122.65. End of Chapter 4 The Universal Formula The illustration number 7 shows how Dhruvaloka and the 7 Sages and the constellations are to be calculated together. Theses objects move in the same time. Bhagavatam finds them aligned in this way. Mayesa Dasa Chapter 5 The Universal Formula In Srimad Bhagavatam 5th Canto Chapter 23 translated by AC Bhaktivedanta Prabhupada we read in the purport to text 9 how Maharloka is above Dhruvaloka and then comes Janaloka and then Tapoloka then Satyaloka,etc. Now we shall calculate these and diagram. From now on I shall be adding the cumulative numbers in a different way to save time. it should be clear what I am doing. For example if the suns axle is 31500000 plus 800000 for the moon then the next calculation (for the constellations will add in 2400000 for the constellations on top of 31500000 and 800000 ) Maharloka We begin with Maharloka which is said to be 80000000 miles above Dhruvaloka Formula Axle of sun plus added numbers is 141100000 Bhuhulasva plus added numbers 773084901.3 / 360 = 2147458.059 141100000 / 2147458.059 = 65.70559057 We must now use the circumference of the universe. That circumference is 12566370610 (4320000 X 12566370610) / (1577917828 + 4320000 ) / 65.70559057 =506754.1533 This is the circumference of Maharloka. Maharloka stretches from one side of the universe to the other. Is it a planet or a region of planets? 5067541533 / universe = .403262142 That is cosine 66.21773023 Janaloka Formula axle plus for Janaloka is 933084901.3 Bhuvulasva plus is 301100000 / 360 = 2591902.504 301100000 / 2591902.504 = 116.1694931 Now (4320000 X 12566370610) / ( 1577917828 + 4320000 ) / 116.1694931 = 295345.0885 2953450885 / universe = .235028154 That is cosine 76.40671764 Tapoloka Formula axle plus = 941100000 bhuvulasva plus = 1573084901 1573084901 / 360 = 4369680.281 941100000 / 4369680.281 = 215.3704481 Now (4320000 X Universe) / ( 1577917828 + 4320000 ) / 215.370 4481 = 159304.3385 1593043385 / Universe = .126770365 That is cosine 82.71699636 Illustration 8 shows A Satyaloka B Tapoloka C Janaloka D Maharloka E Dhruvaloka F Constellations G 7 Sages Question - Above the rays of the sunshine by a distance of 100,000 yojanas [800,000 miles] is the moon... The moon is not as regular as the sun. The moon always moves at least 18.28 degrees north and south. But it also moves beyond that. Can you give the exact distance from Earth and then from Meru in miles Answer - Yes the formula will give us that. We appear to be 33,000,000 miles from Meru (above Meru-out from Meru is not far. That can be calculated by right triangle. ) Sun is always on the top of Meru therefore above it. But sun goes around the middle of earth planet. We shall find that distance with the formula. Mayesa Dasa’s Chapter 5 The Universal Formula continued Satyaloka Formula Axle plus = 1901100000 bhuvulasva plus = 1873084901 1873084901 / 360 = 5203013.615 1901100000 / 5203013.615 = 365.3843985 Now (4320000 X universe) / ( 1577917828 + 4320000 ) / 365.3843985 = 93901.35256 939013525.6 / universe = .0747243 That is cosine 85.71461859 Vaikuntha We must now use the circumference of the universe plus the universal shell. That number is 312566370600 Formula Axle plus = 2110700000 bhuvulasva plus = 2082684901 2082684901 / 360 = 5785235.836 2110700000 / 5785235.836 = 364.8425163 Now (312566370600 X 4320000 ) / ( 1577917828 + 4320000 ) / 364.8425163 = 23391.00011 23391.00011 / universe = .000001861 That is cosine 89.99989337 It is not possible to have cosine 90 degrees as cosine of 90 is always equal to 0 End of Chapter 5 The Universal Formula The illustration number 9 shows the universe surrounded by its shells and beyond that Vaikuntha. Understanding the position of the Moon by His Grace Mayesa dasa Srimad Bhagavatam 5th canto chapter 7 text 8. Above the rays of the sunshine by a distance of 100,000 yojanas [800,000 miles] is the moon. The moon is not as regular as the sun. The moon always moves at least 18.28 degrees north and south. But it also moves beyond that. Formula for the moon Step one 31,500,000 + 800,000 = 32,300,000 Step two (640,884,901.3 + 2,400,000) / 360 = 1,786,902.504 Step three 32300000 / 1786902.504 = 18.07597221 Step Four 18.07597221 X 1577917828 =285223988 / 8 = 3565299851 When we subtract 35652998.51 from 706489952.8 we get 670836954.3 670836954.4 is the moon at 18.28 degrees exactly Now we can diagram this Illustration 3 shows the diagram of the moon from the side at 18.28 degrees, which we derive from the code of Srimad Bhagavatam 5th canto chapter 9 text 1 Diagram 4 shows us the diagram of the moon and the diagram of Rahu at 11.39 degrees, overlaid. The line AB is the moons angle of 18.28 AC is degree 11.39 AD is moons angle of zero degrees AE is moons angle of 11.39 AF is moons angle of 18.28 When the moon is not more than 11.39 lunar eclipse of the full moon can take place. As we continue we shall explain how the moon moves further away than the sun sometimes. And we shall demonstrate the logic of phases. And we shall speak at length about rahu and give quotations to bulwark our discovery of the formula. Mayesa Dasa’s Chapter 6 The Universal Formula More about the sun We have said the sun moves towards and away from the planet on which we reside. We have shown that the formula indicates this. now let us look at some confirmation from sastra. The Matsya Puranam Volume 1 page 528 Published by Nag Publishers The sun from his position draws water of Dhruva in molecular form...The sun is the centre of clouds. he absorbs water by his bright rays. his rays with the help of air draw out water from the ocean. but by means of white rays he obtains rain from the clouds in due seasons....Such rain falls for six months for the good of the creation...The sun established by Dhruva is the creator of rain. In the Srimad Bhagavatam there is a verse about the movement of the sun. Srimad Bhagavatam Canto 5 Ch 22 Text 7 The sun god has three speeds-slow,fast and moderate... Now let us understand this. The sun, nor any object in the universe moves from slow to middle to fast without interim movement. The sun moves around us every day. For 182.625 days he moves north and for the same period he moves south. In the winter you look south-east for the suns rising and in the summer you look to the north-east for the suns rise. That means the sun moves north and south as it moves around us. The meaning of the Bhagavatams verse is that there is an extreme fast and extreme slow and a middlemost movement. The sun does not jump to the middlle and maintain that and then jump to the slowest. Everyday the sun is either moving closer or moving farther away until it reverses its direction north and south without reversing its direction in its circular movement. As the sun moves around us if it is moving say 28800000 miles in 48 minutes, it travels very fast and when it moves less distance (when it is closer) it moves slower. In this way although the sun has different distances from us it covers 360 degrees. That speaks of a supreme control over the sun, and other planets as well. With the help of the formula we can estimate the suns distance from us at any given moment. Antariksa Srimad Bhagavatam 5th Canto Ch 24 Text 5 Beneath Vidyadhara-loka, Caranaloka and Siddhaloka, in the sky called antariksa, are the places of enjoyment for the Yaksas, raksasa, pisacas, ghosts and so on. Antariksa extends as far as the wind blows and clouds float in the sky. Above this there is no more air. In the bahgavatam itself we have no measurement but in the acharyas commentaries we get measurement. Commentaries on 5th Canto Published by Gopsons paper Lmtd By HDG Danavir Gosvami Maharaja 5th Canto Ch 9 text 5 Commentary by Bhagavatprasadacharya ...It is 9,900 yojanas in its depth, where winds blow strongly and clouds are observed. Formula Step One 31500000-(80000+80000+79200)=31260800 Step Two 640884901.3-(80000+80000+79200)=640645701.3 Step Three 640884901.3 / 360 = 1779571.393 Step Four 31260800 / 1779571.393 = 17.56627961 Step Five 17.56627961 X 1577917828 = 27718145770 / 2 = 1385907288 Now we have already found the constellations to be 2168572242 So let us subtract 2168572242 - 138590728.8 = 2029981513 When we divide 2029981513 by 2168572242 = .936091256 .936091256 is cosine 20.59483388 What stars or group of stars are at that declination? We find a very famous one. It is called Canis Majoris. In its center is a very famous star called by some the Dog Star. The Dog Star has been very famous recently as figuring in an ancient tribe on earths religious rituals. Also it is known as the largest star in the universe. It lies at approximately -20 degrees. Illustration 10 shows the location of the constellation known as Canis majoris which travels with the constellations as it is also a constellation. Earth (Bhutulasva) Srimad Bhagavatam 5th Canto Ch 24 Text 6 Below the abodes of the Yaksas and Raksasas by a distance of 100 yojanas[800 miles] is the planet earth. Its upper limits extend as high as swans, eagles and similar large birds can fly. Formula Step One 31500000 - ( 80000 + 80000 + 79200 + 800 ) = 31260000 Step Two 640884901.3 - (( 80000 + 80000 + 79200 + 800 ) = 640644901.3 Step Three 640644901.3 / 360 = 1779569.17 Step Four 31260000 / 1779569.17 = 17.56604943 Step Five 17.56604943 X 1577917828 = 27717782560 / 2 = 13858891280 Now let us subtract from Canis Majoris 2029981513 - 1385889128 = 644092385.2 This number should be perhaps 640884901.3 This is bhutulasva. That only means that the number we have chosen for the constellations is off a decimal point or two. If we divide this number by the constellations we get .297012187 which is cosine 72.72176379 degrees However we may not be getting a valid declination here. In other words we may not be able to divide bhutulasva by constellations and get a useful number. What must be kept in mind with bhutulasva is that it does not move. It is stationary. The planet earth referred to in 5th canto then is bhutulasva. With the formula we are not given the planet earth on which we reside but we may be able to work out its location in respect to the other planets, mathematically. Meru Meru and the earth planet on which we reside are sometimes pictured side by side. That is not possible from the evidence in bhagavatam. Srimad Bhagavatam 5th Canto Ch 21 Text 8-9 The living entities residing on Sumeru Mountain are always warm, as at midday, because for them the sun is always overhead. As the sun is going around this planet on which we reside producing night and day but not on Meru, that gives us a clue. Srimad Bhagavatam 5th Canto Ch 21 Text 7 ...On Manasottara mountain, due east of mount Sumeru, is a place known as Devadhani, possessed by king Indra. Similarly, in the south is a place known as Samyamani, possessed by Yamaraja, in the west is a place named Nimlocani, possessed by Varuna, and in the north is a place called Vibhavari, possessed by the moon-god.Sunrise, midday, sunset and midnight occur in all those places according to specific times , thus engaging all living entities in their various occupational duties. Here we see that on bhutulasva there are four cities over which the sun passes creating day and night. Therefore the sun must be above them. Illustration 11 A is the planet earth we reside on B is Mount Meru or Sumeru mountain C is Bhutulasva ( Seven circular islands and seven circular seas) D is the sun. We can note that the sun is positioned directly over the outskirts of bhutulasva so that it may shine down on the four demigod cities mentioned in 5th canto ch 21 Text 17 Srimad Bhagavatam as it moves around. We can note it is positioned so that its rays are always shining down on the top of Meru. We can note that it is positioned to create day and night on the earth planet on which we live as it circles around and above bhutulasva.
Posted on: Tue, 26 Aug 2014 13:41:03 +0000
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