2aii) Determine the value of y, when x=9 Y= a + b 1/√x Y = 0 + 2 1/√9 Y= 0 + 2(1/3) Y= 0+2/3 , = 2/3 12a) X. | No of absent | Fx. 1. | 40. | 40 2. | x. | 2x 3. | 25. | 75 4. | 50. | 200 5. | 35. | 175 6. | 2x. | 12x Total. | Ef=150+3x. | Efx= 490+14x To find the value of x, since the total number of absents Ef = 240 150+3x = 240 3x = 240-150 3x= 90 X= 90/3, 30 If x= 30 , Ef = 150+3(30)=24 Efx = 490 + 14(30) = 910 Mean = Efx/Ef = 910/240 = 3.79 * Absent for six days = 2 x 30 = 60 absent * at least a day 40 + x + 25 + 50 40 + 30 + 25 + 50 = 145 absent 3a) Given that V= √gx (1+3h) V^2 = gx ( 1 + 3h ) V^2 = gx + gx ( 3h/x) V^2 – gx = gx3h/x X( V^2 – gx ) = gx3h X^2 V^2 – gx^2 = gx3h h = x^2 V^2 – gx^2/3gx. (Where ^ is raise to power) 3b) Value of H, when V=25 , g=10, x=15 h(15^2 x 25^2) – ( 10 x 15^2 )/ 3 x 10 x 15 h( 225. X 625) – (2250)/ 450 h( 138,375) /450 h= 307.5 4a) The sum of in interior angles of a n- side convex polygone is ( 2n-4 ) right angles 3:2 ( interior and exterior ) ( n-2 )180 = 360o X(3-2 x 180)= 360o 360/180 X= 2 4b). Xy=14cm, XZ=7cm, PZ=3cm, YP=? PZ/YB = XZ/XY 52/7 = 7YB/7 YB= 7.43cm YZ = PZ + YB YZ = 3 + 7.43 YZ= 10.43cm 5a) a+b+c+d+e+f+g+h /8 = 10 ——— (I) a+b+c+d+e+f+g/ 7 = 9 ———– (ii) a+b+c+d+e+f+g+h = 80 a+b+c+d+e+f+g+ = 63 h= 80-63 h= 17 5b) Rice —— 2 Pineapple —–3 Cassava …….6 Sugarcane—- 4 Cocoa————5 TOTAL::::::: 20 * Rice = 2/20 x 360 = 36 * Pinaple = 3/20 x 360 = 54 * casava = 6/20 x 360 = 108 * sugar = 4/20 x 360 = 80 * cocoa = 5/20 x 360 = 90 7ai) Materia = 3 Labour = 5 Profit————–> 23% Materials = 3/8 x 95000 = #35,625 Profit of materials at 23% = 23/100 x 35625 = #819.751 At 23% profit the material cost #35625 + #8193.7 = # 43818.75 At 18% = 18/100 x 35625 = #6412.5 Cost sold to consumer =# 35.625 + 6412.5 = # 42,037.5 7aii) Labour = 5/8 x 95000 = 59,375 7b) cost of materials = #35,625 Since there is no increase in the cost of labour 15/100 x 35,625 = # 5343.75 The 15% increase = 35,625 + 5343.7 #40,968.75 Verified Maths Type D
Posted on: Mon, 07 Jul 2014 10:34:16 +0000
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