Answer key to the Model Paper (CSAT) held on 20.07.2014 1. C • Statement 2: The passage refers to innovation and enterprise as well as gives various examples of the same in reference to Gosavi Group. 2. A • Innovation should be promoted for specific techniques for different sections of population to be catered by non-formal education. 3. C • Refer to paragraph 1. 4. A • A strong economy is in consonance with the concept of nationalism, though in its modern avatar. 5. B • Refer to the last paragraph. • Also it is the lack of accountability of civil services to the legislature that is a threat. 6. B • The passage deals with only the concept of governance by the founding fathers, not all the major aspirations (as enshrined in the Preamble). 7. C • Refer to Paragraph 1. 8. B • Judiciary and media have helped improve government services. There is no mention of their role in bottom-up delivery of services. 9. D • Refer to the last paragraph. 10. C 11. A • SDG: Refer to Paragraph 2. • MDG: Refer to 1st sentence of last paragraph. 12. C • Statement 1: refer to paragraph 2. • Statement 2: refer to paragraph 1. 13. C • Statement 1: refer to sentence 3, paragraph 3. • Statement 2: refer to last sentence, paragraph 3. 14. B • UN is collaborating with the countries for reviewing the progress on the parameter of MDG, and is not conducting the review on its own. 15. C • Statement 1: refer to second sentence of paragraph 1. • Statement 2: refer to first two sentences of paragraph 2. 16. C 17. C 18. A Explanation – Simplest solution – First letter of each pair is the next alphabet of the last letter of preceding pair and second letter is the one alphabet before the first letter of the following pair. Hence, V is the first letter as it is next alphabet to U (PU) and B is the second letter which is one letter before C (CJ). Hence, correct answer is VB. 19. C Explanation – (1O + 3P + 2T = 45) * 3 (3O + 2P + 4T = 110) *1 ----------------------------- 6O+11P+10T = 245 ----------------------------- Hence, answer is Rs. 245 20. A Explanation – 3C2 * 4C1 * 5C2 + 3C2 * 4C1 * 5C3 = 3*4*10 + 3*4*10 = 120 + 120 = 240 21. C Explanation – Middle term in each row is equal to the sum of the first term and square of the third term. 5 + 42 = 21 22. C Explanation – Everyday, car climbs a total of 1m. By end of 17th day, it will climb 17 meters and on 18th day, it will climb 3 meters in the day and will reach on top. 23. B Explanation – Graph is between total amount paid and unit consumed and not between price of each unit and unit consumed. Hence, graph (A) is not the right graph. 24. A Explanation – In first case, length of the rope is sqrt (82 + 152) = 17 In second case, length of the rope is sqrt (82 + 62) = 10 Hence, 7m less rope is required. 25. C Explanation – Cost Price per Mango = 64/8 = Rs. 8 Proft percentage = 25% Hence, profit earned is 0.25 * 8 = Rs. 2 Total mangoes need to be sold to earn Rs. 40 as profit = 40/2 = 20 mangoes 26. C Explanation – Lets assume the distance between city X and city Y is 60km (I took 60 for simplicity as one train takes 6 hours and another 3 hours. 60 is divisible by both) First train will travel with speed of 60/6 = 10mph and it will cover 20kms by 11 am. Second train will start at 11 am at a speed of 60/3 = 20kmph. At 11 am, the distance between the two trains is 60-20 = 40 kms and their relative speed is 10+20 = 30kmph (as the trains are tavelling in opposite direction). Hence, they will take 40/30 = 4/3 hours to cross each other after 11 am. That time will be 12:20 pm. 27. D 28. C • Refer to paragraph 1. 29. D • Industrialization could not impart industrialism i.e. values 30. C • Cultural vacuum was created as they could not practice their own culture nor could they participate in the cultural activities of the urban-industrial centers. 31. A 32. C • Statement 1: refer to sentence 5 of Paragraph 1. • Statement 2: refer to sentence 2, paragraph 1. 33. A 34. C • Refer to last paragraph. 35. A 36. B 37. C Explanation – Right side picture is part of left side picture but not the complete one. 38. B Explanation – Sequence is 2 ‘plus signs’ then 3 square. Hence, it will be ‘plus’ sign. First two plus signs have same shades, next two has alternate shades and next two has same shades. Hence, it should be horizontally shaded ‘plus’ sign. 39. B 40. C 41. D 42. B 43. D Explanation – Order of Rahul, Rohit and Rahim is not clearly given. Hence, positions cannot be determined. 44. D Explanation – Ishita’s new running speed is 9 kmph (3 kms in 20 minutes). 1400 calories when she ran 2 kms at 5 kmph speed. Calories when she runs 3 km at 9kmph = 1400*3/2*9/5 = 3780 calories 45. C Explanation – When car travels 1 km then 4 tyres travel 1 km each. Hence, total distance travelled by tyres is 4 kms. In the same way when car travels 10,000 kms then tyres travel total distance of 40,000 kms. This distance need to be distributed among 5 tyres equally i.e. 40000/5 = 8000 kms by each tyre. 46. D Explanation – Assume speed of the boat in still water is b kmph. Speed of stream would be b/3 kmph Speed of boat in upstream is b-b/3 = 2b/3 Given speed is 60 km/3 hr = 20 kmph 2b/3 = 20 => b/3 = 10 kmph Hence, speed of stream is 10kmph. 47. C Explanation – For a number to be divisible by 4, last two digit should be divisible by 4. Hence, with digits 1 to 6, the last two digit numbers would be 12, 16, 24, 32, 36, 52, 56, 64. All these numbers have four options of third digit. For example in case of 12 as last two digit, 312, 412, 512, 612 are possible three digit number divisible by 4. In the same way, 4 numbers for each of the 8 two digit numbers mentioned (12, 16, 24, 32, 36, 52, 56, 64). Hemce, total possible numbers are 4*8 = 32 48. C Explanation – On the blockage day, rate of actual filling would be I1 + I2 – O1/2 – O2 = 10 + 5 - 4/2 – 2 = 11 litres per hour. It took 18 hours, hence capacity of the tank is 18*11 litres On a normal day, rate of filling would be I1 + I2 – O1 – O2 = 10 + 5 – 4 -2 = 9 litres per hour Hence, it will take 18*11/9 = 22 hours to fill the tank. 49. B Explanation – Rhombuses (Rhombii) are same as squares in this case. We just need to rotate the figure by 450. We have already discussed in the class that how to find total number of squares of all sizes in a square of n*n size. It is equal to 12 + 22 + … + n2. This is, in turn, equal to n(n+1)(2n+1)/6. Hence, in this case, it is going to be 4*(4+1)*(2*4+1)/6 = 4*5*9/6 = 30 50. B Explanation – Total value is going to be 10000*(1.1)3*(1+3*0.1) = Rs. 17303 51. C Explanation – As discussed in the class, for zeroes in the last, we need to have multiples of 2 and 5. In f(7), we will have only 2 multiples of 5 (in 52). Hence, two zeroes. 52. B Explanation – 2013 (Totalemp.=22000) Percentage Absolute no. of employees Dep 1 12 2640 Dep 2 15 3300 Dep 3 18 3960 Dep 4 27 5940 Dep 5 28 6160 2014 (Totalemp.=25000) Percentage Absolute no. of employees Dep 1 15 3750 Dep 2 17 4250 Dep 3 21 5250 Dep 4 23 5750 Dep 5 24 6000 Dep 4 in 2014 has 23% of total employees (25,000) = 0.23 *25000 Dep 5 in 2013 has 28% of total employees (22,000) = 0.28 *22000 Dep 4 in 2014 is how many time dep 5 in 2013 = 0.23*25000/(0.28*22000) = 0.93 (approx) 53. D Explanation – No. of employees in dep 2 in 2013 = 0.15 * 22000 = 3,300 No. of employees in dep 2 in 2014 = 0.17 * 25000 = 4,250 If 400 employees left after 2013, that means only 3300 – 400 = 2900 left. But, in 2014, data shows that there are 4250 employees. Hence, 4250 – 2900 = 1350 new employees joined the department. 54. A Explanation – Variation in dep 1 = (0.15*25000 – 0.12*22000)/(0.12*22000) = 0.42 i.e. 42% This is the highest variation as compared to the other options. 55. C Explanation – Percentage increase in dep 3 = (0.21*25000 – 0.18*22000)/(0.18*22000) = (5250-3960)/3960 = 32.58% 56. B Here, repeated block is ‘abxdm’. Now, abxdmabxdmabxdm 57. C The last letter of each block of five letters is brought in the beginning of the next block. 58. A 59. D 60. A 61. B 62. A 63. B 64. A 65. A Explanation – Year No. of students who joined the school No. of students who left the school No. of students studying 2009 300 350 3950 2010 250 300 3900 2011 450 250 4100 2012 150 450 3800 2013 300 500 3600 2014 550 350 3800 66. B Explanation – In 2012, no. of students left are 450 and in 2011 no. of students left are 250. Hence, the rise in no. of students left is (450-250)/250 = 80%. This is highest as compare to other years. 67. A Explanation – It is a decrease of (4100-3800)/4100 = 7% (approx) 68. C Explanation – No of students studying in 2010 = 3900 No of students studying in 2013 = 3600 Hence, percentage is 3600/3900 = 92% (approx) 69. B 70. A 71. A 72. D 73. C Explanation – K’s rank from the top = 30 – (3+5)=22nd K’s rank from the bottom = 30 – (22-15)=9nd K’s rank from the bottom = 30 – (4+17)=9nd Therefore, either of Statement I and II is sufficient to solve the question. 74. D na ja ho – how any why …(i) ja pit ka – how they went …(ii) Code for pit cannot be determined even using both the statement. 75. B • The consultation process creates an environment conducive for acceptability of the change. • Participatory mechanism leads to better implementation. 76. D • The project is running against a stiff timeline and needs a person immediately; hence the project manager should be provided with one. • Since there is a shortage of employee, HR department can resolve the issue in long term. 77. C • The fundamental principle of balancing the needs of ecology and development should be met while demarcating any such area. It should the first step before any EIA is done or approval given or denied. 78. B • Immediate arrangement of treatment and preventing the spread is necessary. 79. C • Protection should be provided for the exercise of legal rights of the individuals. At the same time arrangements for maintaining law and order should also be made. 80. C • You are heading a committee for the decision on raising the limit of foreign investment. The committee has to look into various aspects including the status and requirements of our economy as well as global scenario. Hence, any decision should be reached after taking these aspects into consideration.
Posted on: Tue, 05 Aug 2014 06:23:25 +0000
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