Find 3 consecutive even integers such that 4 times the first is decreased by the second is 12 more than twice the third. Ok Im not understading the is decreased by the part so I assume it was a typo and you just meant Find 3 consecutive even integers such that 4 times the first is 12 more than twice the third. 4 times the 1st would be just 4x and is equal to 12 more than twice the 3rd which would be (x + 4) * 2 + 12 which is... 4x = (x+4)*2 + 12 4x = 2x + 8 + 12 2x = 20 x = 10 So the answer would be 10, 12, 14 to check 4(10) = (14)*2 + 12 40 = 28 + 12 40 = 40
Posted on: Fri, 01 Nov 2013 09:03:49 +0000
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