I just read a comment about this being BS because they said this,,,,, which I can not see how it disproves anything but instead points toward the fact there DOES seem to be a DIVINE CODE within mathematics,,,. ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, ,HERE IS THE STATEMENT AGAINST THIS PRESENTATION OF MATH AND THE DIVINITY WITHIN THE NUMBERS 3. 6. & 9 ,,,,,,*)(*)(*)(*)(*)(*)(*........................ This theory can apply to numbers with any base Lets take hexadecimal Has 16 digits, 1,2,3,4,5,6,7,8,9,A,B,C,D,E,F,0 The sum of all digits exept F is 69 (hexa) Now add 6+9 Answer is F Paradoxically F plus any digit returns the same digit i.e 8+F=17 (1+7=8) And F also equals all the digits of hexadecimal and 69(hexa) and nothing (0) like is in this video Now lets go to the circle thing 360 hmm? its 9(last number of decimal)*4*10(its 9+1) Now apply it to hexadecimal F(last number of hexadecimal)*4*10(its F+1 in hexadecimal) F*4*10 = 3C0(all in hexa) 3C0 is the congenial number to the 360 in hexadecimal lets start halving it 3C0/2=1E0 (1+E=F) 1E0/2=F0 (F+0=F) F0/2=78 (7+8=F) 78/2=3C (3+C=F) 3C/2=1E (1+E=F) 1E/2=7.8 (7+8=F) 7.8/2=3.C (3+C=F) and so on, see hexadecimal have even better repeting pattern The resulting angle always reduces to F in this case. Now Polygons, All the polygons have congenial sum of external angles of 3C0 in hexadecimal In triangle sum of the angles will be 1E0 (1+E=F) Quadrilateral - 3C0 (3+C+0=F) Pentagon 5A0 (5+A+0=F) Hexagon 780 (7+8+0=F) Heptagon 960 (9+6+0=F) Octagon B40 (B+4+0=F) Nonagon D20 (D+2+0=F) Dacagon F00 (F+0+0=F) Now u tell me is there a divine code embedded in our number system? or its just a pattern comes with last digit of number system of every base. Just calculate this with number system of any base and see for yourselves, the last digit of number system you choose, will be your divine number
Posted on: Tue, 06 Jan 2015 05:44:55 +0000
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