NECO MATHS Maths Type A 1-10: DBBADBABEE 11-20: - TopicsExpress



          

NECO MATHS Maths Type A 1-10: DBBADBABEE 11-20: CABBEEBBBC 21-30: BCDEBCBCDB 31-40: AEBCDAEDBD 41-50: ABADCEBAED 51-60: BEBDBEDEDA Maths TYPE B 1-10: CABBAEBACC 11-20: AEBCDAEDDB 21-30: DEBDBEDEDC 31-40: BBBABBABED 41-50: ECDEBBDBBC 51-60: ADADCECAED Maths TYPE C 1-10: BEBDAEDEDA 11-20: EDAEBBDBAB 21-30: ADADDCABEA 31-40: AABBCAEDDB 41-50: DBDBABBBCC 51-60: BBBAEBABEE Maths Type D 1-10: ABADCEBAED 11-20: BBBAEBABEE 21-30: AEBCDAEDDB 31-40: DCDEBCBCDB 41-50: BEBDBEDEDA 51-60: CABBEEBABC +++++++++++++++++++ PLS TAKE NOTE: ^ means Raise to power ============= root means square root sign ie _/ ============= As a maths student u knw wat base means eg: 244basen means 244n. ============ degree is a degree sign that looks like zero on top. =========== * means multiplication ============ ++++++++++++++++++++++++++ (1) (a) peugeout sector= 180/480*(360) =135 degree datsun sector= 108/480*(360) ford sector= 72/480*360 =54 degree toyota sector= 56/480*(360) =48 degree (1b) Pr(toyota)= 42/480 Pr(volkswagen)= 48/480 Pr(toyota or volkswagen)= (42/480)+ 48/480 =90/480= 9/48 =3/16 =========================== (2) (a) given (a^2-4b^2) =(a^2-4b^2)/(a^2-3ab-2ab+6b^2)=(a^2-4b^2)/(a(a-3b)-2b(a-3b) =a^2-(2b)^2/(a-2b)(a-3b))= (a-2b)(a+2b)/(a-2b)(a-3b) =a+2b/(a-3b) (2b) forth term(f4)=-3 ninth term(f9)=123 fn=a+(n-1)d f4=a+3d f9=a+8d a+3d=-3, eqn (1) a+8d=12, eq(2) subtract eq(1) from eq(2) a-a+8d-3d=12-(-3) 5d=15 d=15/5=3 using eq(1) a+3d=-3 a+3(3)=-3 a+9=-3, a=-3-9 (i) common difference(d)=3 (ii)sum of the first seven terms sn=n/2(2a+(n-1)d) s7=7/2 ============================ (3a) 13/4 +X/Y = 4/3 X/Y=4/5-13/16 X/Y=64-65/(16)(5) X/Y= -1/80 X:Y = -1:80 (3b) cost each machines = 25,000/12 = 2083.3naira. (i) cost of machines = 2083.3 *10 =20833.30 (ii) number of such machines = 175,000/2083.3 =84 machines ============================== (4) (i) draw a venn diagram U = universal set =40 mangoes (M) = 15 Pineapples(P)= 21 (ii) let X reps the no. that do not like mangoes and pineapples (ii) 9+6+15+X = 40 30+X =40 X = 40-30 X =10 (iii) . % of class of mangoes only = 9/40 * 100 = 22.5% =============================== (5) (a)244basen=1022base4 2*n^2+4*n^1+4*n^0=1*4^3+0+4^2+2*4^1+2*4^0 2n^2+4n+4=64+0+8+2 2n^2+4n+4=74 2n^2+4n+4-74=0 2n^2+4n-70=0 n^2+2n-35=0 n^2-5n+7n-35=0 n(n-5)+7(n-5)=0 n+7=0 or n-5=0 n=-7 or n=5 (b)Using similar triangle AZ/XZ=KZ/YZ 8/XZ=11/24 XZ=(8*24)/11 =17.45cm ============================= (6) (i) using pythagoras OQΛ2 = ORΛ2 + QRΛ2 15Λ2 = 6Λ2 + QPΛ2 QRΛ2 = 225 - 36 QRΛ2 = 189 , QR = SQR OF 189 QR = 13.75cm lenght of chord = PR + QR = 13.75 + 13.75 = 27.50cm (II) Lenght of chord (PQ) = 2r sin(tita/2) , r = 15cm 27.50 = 2*15*sin(tita/2) sin(tita/2) = 27.50/30 sin(tita/2) = 0.9165 tita/2 = sinΛ-1(0.9165) tita/2 = 66.42 tita = 66.42 *2 tita = 133degree (iii) perimeter = lenght of arc + lenght of chord lenght of arc = tita/360 *2(pile)r = 133/360 * 2 *22/7 *15 = 34.83cm. perimeter (P) = 34.83 + 27.50 = 62.30cm = 62.3cm. ========================== (8) PLS TABULATE THIS LIKE A LOGARITHM TABLE. No: 10900,root3 10900, 392.9, (392.8)Λ3, 39.436, 12.03. (12.03)Λ3, 39.436*(12.03)Λ3, (root3(10900)*(392.8)Λ3)/((39.436*12.03)Λ3), antilog 1.96*10Λ4 Log: 4.03744, 4.0374/3= 1.3458, 2.594.2, 2.5942*(3)= 7.7826, 1.3458, 7.7826, 1.5959, 1.08003,1.0803*3=3.2409, 1.5959*3=3.2409, 1.5959+3.2409=4.38368, 9.1284, 4.8368, 9.1284+ 4.8368=4.2916. =========================== (9) Total surface area(A)=88cmΛ2 Height (H)=7cm (i)A=2*pie*r*h+2*pie*rΛ2 A=2*pie*r(h+r) 88=2*22/7*r(7+r) 88=6.29*r(7+r) 7r+rΛ2=88/6.29 7r+rΛ2=14 rΛ2+7r-14=0 using almighty formular r=-7+_root(7Λ2-4*1*-14)/2 r=-7+_root(49+56)/2 =-7+_root(105)/2 =-7+_10.25/2 r=-7-10.2/2 or-7+10.25/2 r=-8.625 or 1.625 Diameter(d)=2r 2*1.625 =3.625 (ii)Volume of the solid(v) =pie*rΛ2*h =22/7*(1.625)Λ2*7 =406.66/7 =58.09cmΛ3 (9b)
Posted on: Mon, 07 Jul 2014 12:45:14 +0000

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