OK, Here is another one. I made some corrections that people suggested. The following problem will ask you to make up the desired length legs using the following: Steel: 2’, 2.5’, 5’, 10’, 20,’ 30’, and 50’ lengths, 3 ft and 5ft Deck Chain, Shackles: 5/8” (2.375”). Deck Chain Links = 3.174”. Basket length is stated as part of the problem and will use the quick method of calculating the ELOH as described in Chapter 18 of RMMS. Overview. The I Beams in an arena are 32” x 26” and spaced 20 ft apart. Basket will be a Split 15 ft. The heights of the beams to the arena floor are 100 ft for Beam A and 99 ft for Beam B. The bridle point will be a maximum distance of 80 ft and a minimum distance of 65 ft to the floor. The Bridle Point can be anywhere along the 80 ft to 65 ft minimum and maximum distance. The apex will be 12.5 ft from Beam B. Base length of Leg 1 will be 25 ft. 7A: Calculate the ELOH of the basket for the two 32”x 26” I beams including shackles. Basket is a split 15 ft. 7B: Calculate the length of Bridle Leg 1 with the ELOH and shackles if the Base length of the steel is to be 10’-0”. 7C: Calculate the Vertical distance using a variation of the Pythagorean Theorem for Leg 1 and Leg 2. 7D: Find the total length of the hypotenuse for Leg 2. 7E: Calculate the distance needed to complete Leg 2. 7F. Make up the steel and STAC chain (and/or dog bone) necessary for Leg 2.
Posted on: Fri, 14 Mar 2014 19:27:40 +0000
Trending Topics
Recently Viewed Topics
© 2015