^ We assume that each particle has a size of 1.5 {\rm\ {\mu}m}, this means (if we assume that it is a cube) its volume is V_{\rm{particle}} = (1.5 {\rm\ {\mu}m})^3 = 3.38 \times 10^{-18}{\rm\ m}^{3}. If the observable universe, which has a volume of V_{\rm{universe}} = 4 \times 10^{80}{\rm\ m}^{3},[4] is filled with such particles, the total number n of such particles is n=\frac{V_{\rm{universe}}}{V_{\rm{particle}}}=\frac{4 \times 10^{80}{\rm\ m}^{3}}{3.38 \times 10^{-18}{\rm\ m}^{3}}=1.18\times 10^{98}. The number of different ways in which the particles can be ordered at least thats my therom
Posted on: Tue, 11 Mar 2014 11:27:29 +0000
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