What volume of carbon(lv)oxide,measured at s.t.p., would be evolved during the reaction? Na=23,c=12,0=16,molar volume of gas at s.t.p.=22.4 dm3)okay, from the reaction equation, 1mol of Na2CO3=1mol CO2, Amount in 0.025 dm3=CbxVb=0.05 mol dm-3 x 0.025 dm3=0.00125 mol This is equivalent to the amount of CO2 liberated in the reaction. At s.t.p., 1mol of CO2 occupies 22400 cm3 at s.t.p. 0.00125 mol CO2 occupies 0.00125x22400 cm3=28cm3 Answer.
Posted on: Mon, 05 Aug 2013 14:44:45 +0000
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