General Mathematics OBJ & Theory Maths Type A 1-10: - TopicsExpress



          

General Mathematics OBJ & Theory Maths Type A 1-10: DBBADBABEE 11-20: CABBEEBBBC 21-30: BCDEBCBCDB 31-40: AEBCDAEDBD 41-50: ABADCEBAED 51-60: BEBDBEDEDA Maths TYPE C 1-10: BEBDAEDEDA 11-20: EDAEBBDBAB 21-30: ADADDCABEA 31-40: AABBCAEDDB 41-50: DBDBABBBCC 51-60: BBBAEBABEE Maths Type D 1-10: ABADCEBAED 11-20: BBBAEBABEE 21-30: AEBCDAEDDB 31-40: DCDEBCBCDB 41-50: BEBDBEDEDA 51-60: CABBEEBABC MATH ESSAY ANS 2) Y= a + b 1/√x When y=2, x=1 and y=6, x=4 The relationship = Y= a+b 1/√x 2 = a + b 1/√1------------(I) 6 = a + b 1/√4------------(ii) 2 = a + b------------- (I) 6 = a + 0.5b---------(ii) -a + b =2 a - 0.5b=6 --------------------- 0.5b = -4 b= 2 Put b in equ 1 2 = a+b 2 = a+2 a = 0 2aii) Determine the value of y, when x=9 Y= a + b 1/√x Y = 0 + 2 1/√9 Y= 0 + 2(1/3) Y= 0+2/3 , = 2/3 3a) Given that V= √gx (1+3h) V^2 = gx ( 1 + 3h ) V^2 = gx + gx ( 3h/x) V^2 - gx = gx3h/x X( V^2 - gx ) = gx3h X^2 V^2 - gx^2 = gx3h h = x^2 V^2 - gx^2/3gx. (Where ^ is raise to power) 3b) Value of H, when V=25 , g=10, x=15 h(15^2 x 25^2) - ( 10 x 15^2 )/ 3 x 10 x 15 h( 225. X 625) - (2250)/ 450 h( 138,375)/450 h= 307.5 4a) The sum of in interior angles of a n- side convex polygone is ( 2n-4 ) right angles 3:2 ( interior and exterior ) ( n-2 )180 = 360o X(3-2 x 180)= 360o 360/180 X= 2 4b). Xy=14cm, XZ=7cm, PZ=3cm, YP=? PZ/YB = XZ/XY 52/7 = 7YB/7 YB= 7.43cm YZ = PZ + YB YZ = 3 + 7.43 YZ= 10.43cm 5a) a+b+c+d+e+f+g+h/8 = 10 --------- (I) a+b+c+d+e+f+g/7 = 9 ----------- (ii) a+b+c+d+e+f+g+h = 80 a+b+c+d+e+f+g+ = 63 h= 80-63 h= 17 5b) Rice ------ 2 Pineapple -----3 Cassava .......6 Sugarcane---- 4 Cocoa------------5 TOTAL::::::: 20 * Rice = 2/20 x 360 = 36 * Pinaple = 3/20 x 360 = 54 * casava = 6/20 x 360 = 108 * sugar = 4/20 x 360 = 80 * cocoa = 5/20 x 360 = 90 7ai) Materia = 3 Labour = 5 Profit--------------» 23- Materials = 3/8 x 95000 = #35,625 Profit of materials at 23- = 23/100 x 35625 = #819.751 At 23- profit the material cost #35625 + #8193.7 = # 43818.75 At 18- = 18/100 x 35625 = #6412.5 Cost sold to consumer =# 35.625 + 6412.5 = # 42,037.5 7aii) Labour = 5/8 x 95000 = 59,375 7b) cost of materials = #35,625 Since there is no increase in the cost of labour 15/100 x 35,625 = # 5343.75 The 15- increase = 35,625 + 5343.7 #40,968.75 12a) X. | No of absent | Fx. 1. | 40. | 40 2. | x. | 2x 3. | 25. | 75 4. | 50. | 200 5. | 35. | 175 6. | 2x. | 12x Total. | Ef=150+3x. | Efx= 490+14x To find the value of x, since the total number of absents Ef = 240 150+3x = 240 3x = 240-150 3x= 90 X= 90/3, 30 If x= 30 , Ef = 150+3(30)=24 Efx = 490 + 14(30) = 910 Mean = Efx/Ef = 910/240 = 3.79 * Absent for six days = 2 x 30 = 60 absent * at least a day 40 + x + 25 + 50 40 + 30 + 25 + 50 = 145 absent. More answer loading:::::
Posted on: Mon, 07 Jul 2014 10:07:17 +0000

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