Reference Notes Reference Notes Tweet Tweet 0 0 5 Share this page: Variation of ‘g’ due to rotation or latitude Latitude Dell Latitude Latitude Longitude Latitude Longitude Finder Chitika | Opt out? Let us consider the earth to be a spherical ball of mass ‘M’ and radius ‘R’. An object of mass ‘m’ is at point P at latitude φ, when the earth is not rotating the weight of the object is mg. But earth is rotating with angular velocity ω. So, the object is moving in a circular path of radius ‘r’ as shown in the figure. The object experiences centrifugal force, The object is being acted by two forces ‘mg’ and ‘F‘. The resultant of these two forces gives the apparent weight of the object (m’g). The resultant of the two forces is given by the diagonal of the parallelogram OPAB. From parallelogram law of vector addition: The value of ω is in the order of 10 . So, the term containing ω is much smaller than 1 and ω so can be neglected. So, acceleration due to gravity is minimum at equator. At poles; φ = 90° g’ = g So, acceleration due to gravity is maximum at poles. Hence, acceleration due to gravity decreases due to rotation while it increases due to increase in latitude. Do you think you can improve this post? Contact us! Find us on Facebook Find us on Facebook Recent Posts Recent Posts Doppler’s Effect Beat Intensity of sound Characteristics of musical sound Vibration in the stretched string Also Visit Also Visit Entrance Preparation Ask Us Colaz Eduindex Academic Career Advice Categories TyroCity Home Entrance Preparation Ask Us News Student Post Did we miss anything? Did we miss your College / School data in this list or is it in wrong category ? Do you want us to add more info. related to your college / school ? Then please feel free to contact us at: info@tyrocity Contact Us General Purpose: info@tyrocity Special Purpose: admin@tyrocity Advtertisement : adv@tyrocity Entrance : entrance@tyrocity Adress: Kathmandu, Nepal Copyright © 2013 TyroCity | Policy Privacy | Disclaimer
Posted on: Thu, 20 Mar 2014 13:03:36 +0000